In the normal approximation to the binomial,
Probability of getting head p = 0.5
Probability of getting tail = 1-0.5 = 0.5
mean=np=20*.5=10
SD=sqrt [npq]=sqrt[10*0.5]=2.236
z value for 14 heads=[14 -10]/2.236=1.789
looking up a z table you will get
P(10<x< 14] = 0.4632 or 46.32 %
ans: 0.4632 or 46.32 %
Probability of getting head p = 0.5
Probability of getting tail = 1-0.5 = 0.5
mean=np=20*.5=10
SD=sqrt [npq]=sqrt[10*0.5]=2.236
z value for 14 heads=[14 -10]/2.236=1.789
looking up a z table you will get
P(10<x< 14] = 0.4632 or 46.32 %
ans: 0.4632 or 46.32 %